# bridge crossing problem greedy algorithm

## bridge crossing problem greedy algorithm

Now, we have calculated the minimum time. Suppose the people cross the bridge in times 1, 2, 5 and 10 minutes. Your job is to determine a strategy that gets all n people across the bridge in the minimum time. i tried to prove it like my text book CLRS : 1.Cast the optimization problem as one in which we make a choice and are Task  is to determine a strategy that gets all 4  people across the bridge in the minimum time. Reason is when highest goes with lowest on another side, time required is of highest. Is it a good idea to shove your arm down a werewolf's throat if you only want to incapacitate them? we combine an optimal solution to the subproblem with the greedy Variable “np” is the total number of people, “bp” is the capacity of the boat & arr[np] gives the timing of “np”th person to cross the bridge. It only takes a minute to sign up. Why does this Excel RIGHT function not work? Asking for help, clarification, or responding to other answers. some people are passing a bridge . Stack Exchange network consists of 176 Q&A communities including Stack Overflow, the largest, most trusted online community for developers to learn, share their knowledge, and build their careers. How many times do you roll damage for Scorching Ray? Optimal solution will only occur when in going trip, number of persons are maximum i.e. When does a topos satisfy the axiom of regularity? These are the conditions of crossing the bridge: The obvious solution seems to be using the fastest guy to take every one to the other end and come back for the rest. It might be faster for the two fastest to go over, one of them go back with the flash light, then the two slowest pass, and finally the second quick person goes back with the light. that makes the greedy choice, so that the greedy choice is always Same number of trips we need to evaluate by the obvious strategy. After each batch, maximum “m*(m-1)” high time persons goes on the another side. We need to first sort the array in which timing values are saved i.e. What are some familiar examples in our solar system, and can some still be closed? In each batch, the proper strategy chosen depends on the minimum time and summation of all time is the minimum time to cross the bridge. What is this symbol that looks like a shrimp tempura on a Philips HD9928 air fryer? What are "non-Keplerian" orbits? By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy. Your job is to determine a strategy that gets all n people across the bridge in the … Are websites a good investment? Is "releases mutexes in reverse order" required to make this deadlock-prevention method work? It only takes a minute to sign up. choice we have made, we arrive at an optimal solution to the original How can I trick programs to believe that a recorded video is what is captured from my MacBook Pro camera in realtime? MathJax reference. How I can know who is calling a REST resource? In obvious solution, we take highest & lowest to go to another side & returns with lowest person. only 2 (or less) people can pass the bridge at the same time in the same direction. Also, I thought the code samples could have been made a bit more readable. Ganesh M Ganesh M. 3,406 8 8 gold badges 24 24 silver badges 25 25 bronze badges. Use Ctrl+Left/Right to switch messages, Ctrl+Up/Down to switch threads, Ctrl+Shift+Left/Right to switch pages. inspired by Arthur. By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy. My Indian flapshell turtle fell from 3rd floor. Do doctors "get more money if somebody dies from Covid”? people passing a bridge (a proof for a greedy algorithm), Creating new Help Center documents for Review queues: Project overview, Shortest time for passing the bridge $t(t_1,t_2,t_3,\dots;\text{Max},\text{Min})$, Using exchange argument in proving greedy algorithm, Proof that the fractional knapsack problem exhibits the greedy-choice property, Greedy Strategy for assigning skis to skiers, Questions on the proof of make change problem using greedy algorithm, Travel time of $n$ people by group: generalizing the Bridge-and-Torch Problem. capacity of the boat. site design / logo © 2020 Stack Exchange Inc; user contributions licensed under cc by-sa. Article Copyright 2014 by Rakesh Waghulde, Finish gives the number of people present on another side, Last Visit: 3-Nov-20 13:41     Last Update: 3-Nov-20 13:41, Download Bridge_Crossing_Puzzle-noexe.zip - 430.3 KB, Download Bridge_Crossing_Puzzle.zip - 430.3 KB. Why is the rate of return for website investments so high? We consider the general problem where the number of people, their individual crossing times and the capacity of the bridge are all input parameters. left with one subproblem to solve. Still, it’s not optimal in some cases. My Greedy solution. it is night and there is only one flashlight . Asking for help, clarification, or responding to other answers. See this puzzle to understand more. Strategy which takes minimum time to travel batch on another side is used. Proof for optimal interval scheduling using a Greedy Approach. Note: Slower person’pace is given by larger time. Is "releases mutexes in reverse order" required to make this deadlock-prevention method work? sorry but what do really chkn and chkr stand for haha? so it must be carried back to the other end of the bridge . Four people come to a river in the night. It is in the category of river crossing puzzles, where a number of objects must move across a river, with some constraints. rev 2020.11.3.37938, The best answers are voted up and rise to the top, Mathematics Stack Exchange works best with JavaScript enabled, Start here for a quick overview of the site, Detailed answers to any questions you might have, Discuss the workings and policies of this site, Learn more about Stack Overflow the company, Learn more about hiring developers or posting ads with us. Benefits of studying annotated grandmaster games, Author has published a graph but won't share their results table. Story. Making statements based on opinion; back them up with references or personal experience. only 1 or 2 people can cross the bridge at the same time in the same direction; the speed of the two people crossing is the same as the slower one; it is night and there is only one flashlight; the people passing the bridge must carry the flashlight; the flashlight cannot be thrown over the bridge so it must be carried back to the other end of the bridge. But only obvious strategy or reservation strategy is not used for full solution. Assume the people are sorted by their passing time increasingly. But how to show the Path in which  we have travelled. The bridge and torch problem (also known as The Midnight Train and Dangerous crossing) is a logic puzzle that deals with four people, a bridge and a torch. By using our site, you acknowledge that you have read and understand our Cookie Policy, Privacy Policy, and our Terms of Service. To learn more, see our tips on writing great answers. Author has published a graph but won't share their results table. share | improve this question | follow | asked Jul 17 '09 at 16:00. At most “m” people may cross at any time, and each group must have a flashlight. Stack Exchange network consists of 176 Q&A communities including Stack Overflow, the largest, most trusted online community for developers to learn, share their knowledge, and build their careers. Is my proof of my greedy algorithm to find subsequence correct? (b) Apply your algorithm to an instance of the problem with n = 4 people, with crossing times of t1 = 1 minute, t2 = 2 minutes, t3 = 5 minutes, and t4 = 10 minutes, respectively. comparing them if $t(p_3) + t(p_1)$ is grater than $2t(p2)$ then the greedy gives a wrong answer . So, we will use batch-1 by reservation strategy. That’s why, while doing such things, make sure that, you have low time persons on the another side so that, they can return with the boat. now i have to assume i have an optimal solution $OS$ and show that i can replace the greedy choice instead of the choice the $OS$ has made . We‘ve not saved any path. problem. I am basically looking for some generalized approach to these kind of problem. Use MathJax to format equations. As explained above, many times, optimal solution is obtained with the reservation strategy. arr[]. To subscribe to this RSS feed, copy and paste this URL into your RSS reader. Do flavors other than the standard Gnome Ubuntu 20.10 support Raspberry Pi on the desktop? This means,  we need to reserve the minimum time persons on the another side and this is the “reservation strategy”. When two people cross the bridge, they must move at the slower person’s pace. I don't see how dynamic programming would work, since there's no obvious decomposition into sub-problems. the speed of the two people passing is the same as the slower one . So, time is highest + second highest. problem. How can I trick programs to believe that a recorded video is what is captured from my MacBook Pro camera in realtime? Would a mouthpiece attachment that does the "work" invalidate the ritual use of the Shofar? The proof In above example, after first batch, 5,6,7,8,9,10 are on another side. The greedy solution involves the one-minute person walking backwards and forwards every time and takes 10+1+5+1+2=19 minutes. A group of “n” people wish to cross a bridge at night. By using our site, you acknowledge that you have read and understand our Cookie Policy, Privacy Policy, and our Terms of Service. Maybe be greedy for something else, such as try to maximize $\min t[D]-\max t[P]$ or something similar? If value of “idnfyarr[idnfy]”=1 then, do it by obvious strategy & if it is 2 then, do it by reservation strategy. MathJax reference. Suppose the people cross the bridge in times 1, 2, 5 and 10 minutes. How to find published article from arxiv preprint, Algorithm for Apple IIe and Apple IIgs boot/start beep. Is it ethical to award points for hilariously bad answers? there seems to be a counterexample for the method . The reason you can't prove that the greedy algorithm is correct is because it isn't. In the above example, reservation strategy takes 26 seconds & obvious strategy takes 27 seconds. Thanks for contributing an answer to Computer Science Stack Exchange! Why can't California Proposition 17 be passed via the legislative process and thus needs a ballot measure?

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